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Proof step 10 from proof datasize-zero-h (previous step)

datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty), buf[m0] = empty, datasize(buf, m0) = 0, n ≤ m0, ∀ buf. datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty) ⊦ buf[n] = empty

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
buf[m0] = empty, datasize(buf, m0) = 0, n ≤ m0, ∀ buf. datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty), ∀ n. n < m0 → buf[n] = empty ⊦ buf[n] = empty

Proof step 10 from proof datasize-zero-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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