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Proof step 12 from proof datasize-zero-h (previous step)

∀ buf. datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty) ⊦ (buf[m0] = empty ⊃ datasize(buf, m0);m0 + 1) = 0, (buf[m0] = empty ⊃ datasize(buf, m0);m0 + 1) = 0 ↔ (∀ n. ¬ m0 < n → buf[n] = empty)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
∀ buf. datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty), ∀ n. ¬ m0 < n → buf[n] = empty ⊦ (buf[m0] = empty ⊃ datasize(buf, m0);m0 + 1) = 0

Proof step 12 from proof datasize-zero-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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