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Proof step 16 from proof datasize-zero-h (previous step)

datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty), buf[m0] = empty, ∀ n. ¬ m0 < n → buf[n] = empty, ∀ buf. datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty) ⊦ datasize(buf, m0) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
buf[m0] = empty, n < m0, ∀ n. ¬ m0 < n → buf[n] = empty, ∀ buf. datasize(buf, m0) = 0 ↔ (∀ n. n < m0 → buf[n] = empty) ⊦ buf[n] = empty, datasize(buf, m0) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic