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Proof step 3 from proof is-encoded-not-garbage (previous step)

is-encoded(a, buf), is-garbage(buf) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ is-garbage(buf) ↔ (∀ a. ¬ is-encoded(a, buf))
Proof step 5:
⊦ is-encoded(a, buf) → (is-encoded(b, buf) ↔ a = b)

Rule argument

spec: <toplevel> name: is-garbage seq: ⊦ is-garbage(buf) ↔ (∀ a. ¬ is-encoded(a, buf)) subst: [buf] → [buf] flags: <all paths>

Additional information

Used simplifier rules: is-encoded-unique: ⊦ is-encoded(a, buf) → (is-encoded(b, buf) ↔ a = b); Used terms: buf