[Imprint][Data Privacy Statement][E-Mail]



View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 20 from proof isempty-append (previous step)

n0 < # buf1, ∀ n. n < # buf0 + # buf1 → (buf0 + buf1)[n] = empty ⊦ buf1[n0] = empty

User applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: n0 + # buf0 abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ m + n < m + n0 ↔ n < n0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s)%n < # buf ⊦ (buf0 + buf)[# buf0 + n] = buf[n]; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer] Used terms: n0 + # buf0