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Proof step 24 from proof isempty-append (previous step)

n < # buf0 + # buf1, ∀ n. n < # buf1 → buf1[n] = empty, ∀ n. n < # buf0 → buf0[n] = empty ⊦ (n < # buf0 ⊃ buf0[n];buf1[n - # buf0]) = empty

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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