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Proof step 10 from proof isempty-elim-right (previous step)

n < # buf0 + # buf1, n < # buf0, n0 < # buf0 + # buf1, n0 < # buf0, n0 < n + m, n ≤ n0, n + m ≤ # buf0 + # buf1, n + m ≤ # buf0, ∀ n2. n ≤ n2 ∧ n2 < n + m → (buf0 + buf1)[n2] = empty ⊦ buf0[n0] = empty, m = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 9 terms: n0

Additional information

Used simplifier rules: ⊦ n < # buf → (buf + buf0)[n] = buf[n]; (s)%append-a: ⊦ (buf + buf0) + buf1 = buf + buf0 + buf1; from specification array-splice[buffer] Used terms: n0