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Proof step 12 from proof isempty-elim-right (previous step)

n < # buf0 + # buf1, n < # buf0, n0 < # buf0 + # buf1, n0 < # buf0, n0 < n + m, n ≤ n0, n + m ≤ # buf0 + # buf1, n + m ≤ # buf0, ∀ n2. n ≤ n2 ∧ n2 < n + m → buf0[n2] = empty ⊦ buf0[n0] = empty, m = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 9 terms: n0

Additional information

Used terms: n0