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Proof step 13 from proof isempty-ext (previous step)

n0 + n < # buf, n1 < n0 + n, n1 + 1 < # buf, n1 < # buf, n0 < # buf, n0 ≤ n1, ∀ n1. n0 ≤ n1 ∧ ¬ n0 + n < n1 → buf[n1] = empty ⊦ buf[n1] = empty, n = 0, isempty(buf, n0, n)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: n1

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m; (s) Used terms: n1