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Proof step 2 from proof eaccess (previous step)

⌊EACCESS⌋ ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ ⌊err⌋ ↔ err ≠ ESUCCESS ∧ err ≠ EEXISTS ∧ err ≠ ENOENT ∧ err ≠ EISDIR ∧ err ≠ ENOTEMPTY ∧ err ≠ ENOTDIR ∧ err ≠ EBADFD ∧ err ≠ EACCESS

Rule argument

Additional information

Used simplifier rules: class: ⊦ ⌊err⌋ ↔ err ≠ ESUCCESS ∧ err ≠ EEXISTS ∧ err ≠ ENOENT ∧ err ≠ EISDIR ∧ err ≠ ENOTEMPTY ∧ err ≠ ENOTDIR ∧ err ≠ EBADFD ∧ err ≠ EACCESS;% ⊦ EBADFD ≠ EACCESS; (s)% ⊦ ENOTDIR ≠ EACCESS; (s)% ⊦ ENOTEMPTY ≠ EACCESS; (s)% ⊦ EISDIR ≠ EACCESS; (s)% ⊦ ENOENT ≠ EACCESS; (s)% ⊦ EEXISTS ≠ EACCESS; (s)% ⊦ ESUCCESS ≠ EACCESS; (s)