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Proof step 3 from proof fail-or-success-prepost (previous step)

⊦ ⟪choose err0 with ⌊err0⌋ ∨ err0 = ESUCCESS in err := err0⟫ (⌊err⌋ ∨ err = ESUCCESS)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 4:
⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪err := err0⟫ (⌊err⌋ ∨ err = ESUCCESS)
Proof step 6:
⊦ ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Rule argument

Additional information