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Proof step 3 from proof inodekey-id (
previous step
)
key.inode? ⊦ inodekey(key.ino) = key
Heuristic elimination applied rule insert elim lemma
And obtained the following new goals
Proof step 4
:
⊦ key.inode? → (m = key.ino ↔ key = inodekey(m))
Rule argument
spec: <toplevel> name: elim-01 seq: ⊦ key.inode? → (m = key.ino ↔ key = inodekey(m)) subst: [key, m] → [key, m]
Additional information
Used terms: key, m