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Proof step 2 from proof isprefix-app-size-ls1 (previous step)

# x1 + # x2 < # x0, x0 ⊑ x1 + x2 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# x1 + # x2 < # x0, x0 ⊑ x1 + x2 ⊦ x0 = []

Rule argument

Additional information

Used simplifier rules: ⊦ # x = 0 ↔ x = []; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic