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Proof step 9 from proof prefixn-split-sublist (previous step)

# y = n0 + n1 ⊦ y = firstn(n0, y) + sublist(n0, n1, y + z)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-del name: sublist-append seq: ⊦ n + m ≤ # x → sublist(n, m, x + y) = sublist(n, m, x) subst: [y, x, m, n] → [z, y, n1, n0] flags: <all paths>

Additional information

Used simplifier rules: ⊦ m ≤ n ↔ ¬ n < m; (ss)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ m < n → ¬ n < m; (s) Used terms: z, y, n1, n0