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Proof step 1 from proof slice-range0 (conclusion)

⊦ slice(n, n, x) = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ slice(n0, n1, x) = (n0 ≤ n1 ⊃ prefixn(n1 - n0, dropn(n0, x));[])
Proof step 3:
⊦ dropn(n, x) = (n ≤ # x ⊃ restn(n, x);[])
Proof step 4:
⊦ prefixn(0, x) = []

Rule argument

Additional information

Used simplifier rules: slice: ⊦ slice(n0, n1, x) = (n0 ≤ n1 ⊃ prefixn(n1 - n0, dropn(n0, x));[]);%dropn: ⊦ dropn(n, x) = (n ≤ # x ⊃ restn(n, x);[]);%prefixn-0: ⊦ prefixn(0, x) = [];% ⊦ m - m = 0; (s)% ⊦ m ≤ m; (s)