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Proof step 5 from proof max-comm (previous step)

n1 ≤ n0 ⊦ n0 = (n1 < n0 ⊃ n0;n1)

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ m ≠ n → (m ≤ n ↔ m < n); (s)