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Proof step 2 from proof min-le-leftn (previous step)

n0 ≤ n1 ⊦ min(n0, n1 + n) = n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ min(n, m) = (n < m ⊃ n;m)
Proof step 4:
n0 ≤ n1 ⊦ (n0 < n1 + n ⊃ n0;n1 + n) = n0

Rule argument

Additional information

Used simplifier rules: min: ⊦ min(n, m) = (n < m ⊃ n;m);