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Proof step 5 from proof ls-add (previous step)

∀ n. n ∈ nx → n < m ⊦ nx < m + n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ nx < m ↔ (∀ n. n ∈ nx → n < m)
Proof step 7:
∀ n. n ∈ nx → n < m ⊦ ∀ n0. n0 ∈ nx → n0 < m + n

Rule argument

spec: <toplevel> name: ls-ext seq: ⊦ nx < m ↔ (∀ n. n ∈ nx → n < m) subst: [m, nx] → [m + n, nx] flags: <all paths>

Additional information

Used terms: m + n, nx