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Proof step 7 from proof ls-ext (previous step)

m0 < m, nx0 < m, m0 < n, n ∈ nx0, m ≤ n, ∀ m. nx0 < m ↔ (∀ n. n ∈ nx0 → n < m) ⊦ n = m0

Heuristic quantifier applied rule all left

And obtained the following new goals

Proof step 8:
nx0 < m ↔ (∀ n. n ∈ nx0 → n < m), m0 < n, nx0 < m, m0 < m, n ∈ nx0, m ≤ n, ∀ m. nx0 < m ↔ (∀ n. n ∈ nx0 → n < m) ⊦ n = m0

Rule argument

pos: left 6 terms: m

Additional information

Used terms: m