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Proof step 8 from proof px-app (previous step)

q0 ⊑ p, ∀ q0. q0 ⊑ p + q → px(user, meta(q0, st)) ⊦ px(user, meta(q0, st))

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: q0

Additional information

Used simplifier rules: a: ⊦ (p + p0) + p1 = p + p0 + p1; from specification list[path]% ⊦ ¬ p ⊑ p0 + p1 → ¬ p ⊑ p0; (s) Used terms: q0