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Proof step 2 from proof px-parent-noneps (previous step)

⊦ px-parent(user, p, st) ↔ px(user, parent(p), st), p = ε

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ px-parent(user, p, st) ↔ p ≠ ε → px(user, parent(p), st)

Rule argument

Additional information

Used simplifier rules: px-parent: ⊦ px-parent(user, p, st) ↔ p ≠ ε → px(user, parent(p), st);