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Proof step 2 from proof parent-elim (previous step)

⊦ q = parent(p) ∧ str = p.last ↔ p = q + str ', p = ε

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ (p + str ').last = str; (s)% ⊦ parent(p + str ') = p; (s)%a: ⊦ (p + p0) + p1 = p + p0 + p1; from specification list[path]%p ≠ ε ⊦ parent(p) + p.last ' = p; (s)