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Proof step 3 from proof prefix-cut-l (previous step)

p + str0 ' ⊑ str1 ' + q ⊦ p = ε, ∃ p0, q1. p = str1 ' + p0 ∧ q = p0 + str0 ' + q1

User applied rule constructor cut

And obtained the following new goals

Proof step 4:
p = str + p1, p + str0 ' ⊑ str1 ' + q ⊦ p = ε, ∃ p0, q1. p = str1 ' + p0 ∧ q = p0 + str0 ' + q1

Rule argument

var: p

Additional information

Used simplifier rules: path freely generated by ε, +;;