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Proof step 8 from proof crash-neutral-recover (
previous step
)
ebm-vol-inv(avol), avol ⊆ avol0 ⊦ ⟨avol := ?⟩ (avol ⊆ avol0)
Heuristic symbolic execution applied rule assign right
And obtained the following new goals
Proof step 9
:
ebm-vol-inv(avol1), avol1 ⊆ avol0 ⊦ ∃ avol. avol ⊆ avol0
Rule argument
Additional information