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Proof step 5 from proof inv-format (previous step)

err = err0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err = ESUCCESS then avol := fill(mkavolume(m), unmapped) else avol := ?⟫ (err = ESUCCESS → ebm-vol-inv(avol))

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

Additional information