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Proof step 5 from proof inv-unmap (previous step)

m < # avol, ebm-vol-inv(avol) ⊦ ⟪avol[m] := unmapped⟫ ebm-vol-inv(avol)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s)%n < # avol ⊦ ebm-vol-inv(avol) → ( ebm-vol-inv(avol[n, aleb]) ↔ ( avol[n].mapped? → # avol[n].data ≤ LEB_SIZE ∧ is-aligned(# avol[n].data, EB_PAGE_SIZE)) → aleb.mapped? → # aleb.data ≤ LEB_SIZE ∧ is-aligned(# aleb.data, EB_PAGE_SIZE)); (ss)% ⊦ ¬ unmapped.mapped?; (s)