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Proof step 14 from proof ebm-cons-above-fillcount (previous step)

# buf = LEB_SIZE, LEB_SIZE = n0 + m0, avols[v][m] = mapped(buf, m0), m < # avols[v], m0 + m1 < LEB_SIZE, is-aligned(m0, EB_PAGE_SIZE), range=(buf, m0, emptyleb, 0, n0), v ∈ avols, m0 ≤ LEB_SIZE ⊦ buf[m1 + m0] = empty

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
# buf = LEB_SIZE, LEB_SIZE = n0 + m0, avols[v][m] = mapped(buf, m0), m1 < n0, m < # avols[v], is-aligned(m0, EB_PAGE_SIZE), range=(buf, m0, emptyleb, 0, n0), v ∈ avols, m0 ≤ LEB_SIZE ⊦ buf[m1 + m0] = empty

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m = m0 + n0 ∧ n < n0 → m0 + n < m; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n < m + n0 ↔ n < n0; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic