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Proof step 18 from proof ebm-cons-above-fillcount (previous step)

# buf = LEB_SIZE, LEB_SIZE = n0 + m0, avols[v][m] = mapped(buf, m0), m1 < n0, m < # avols[v], m1 < LEB_SIZE, is-aligned(m0, EB_PAGE_SIZE), v ∈ avols, m0 ≤ LEB_SIZE, n0 ≤ LEB_SIZE, ∀ n. n < n0 → buf[m0 + n] = empty ⊦ buf[m1 + m0] = empty

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 11 terms: m1

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic Used terms: m1