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Proof step 1 from proof le-inv (conclusion)
⊦ avol1 ⊆ avol0 ∧ ebm-vol-inv(avol1) → ebm-vol-inv(avol0)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
ebm-vol-inv(avol1), avol1 ⊆ avol0 ⊦ ebm-vol-inv(avol0)
Rule argument
Additional information