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Proof step 2 from proof le-unmap (previous step)

ebm-vol-inv(avol), avol ⊆ avol0 ⊦ avol[m, unmapped] ⊆ avol0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# avol = # avol0, ∀ m. m < # avol0 → (avol[m].mapped? → avol0[m] = avol[m]) ∧ (avol[m] = unmapped ∧ avol0[m].mapped? → # avol0[m].data ≤ LEB_SIZE ∧ is-aligned(# avol0[m].data, EB_PAGE_SIZE)), ∀ n. n < # avol0 ∧ avol[n].mapped? → # avol[n].data ≤ LEB_SIZE ∧ is-aligned(# avol[n].data, EB_PAGE_SIZE) ⊦ avol[m, unmapped] ⊆ avol0

Rule argument

Additional information

Used simplifier rules: ebm-vol-le: ⊦ avol0 ⊆ avol1 ↔ # avol0 = # avol1 ∧ (∀ m. m < # avol0 → (avol0[m].mapped? → avol1[m] = avol0[m]) ∧ ( avol0[m] = unmapped ∧ avol1[m].mapped? → # avol1[m].data ≤ LEB_SIZE ∧ is-aligned(# avol1[m].data, EB_PAGE_SIZE)));%ebm-vol-inv: ⊦ ebm-vol-inv(avol) ↔ (∀ n. n < # avol ∧ avol[n].mapped? → # avol[n].data ≤ LEB_SIZE ∧ is-aligned(# avol[n].data, EB_PAGE_SIZE));