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Proof step 13 from proof initialization (previous step)

avols = ∅, n = m, v = default-volid ⊦ ⟪if ¬ v ∈ avols then {fail_or_success#(; ; err); if err = ESUCCESS then avols[v] := fill(mkabstractvolume(n), erased)} else abort⟫ ( (err = ESUCCESS → ⟨ebm_avol_format#(m; ; avol0, err1)⟩ (avol0 = abs(avols[default-volid]) ∧ ESUCCESS = err1)) ∧ (err ≠ ESUCCESS → (∀ avol. ⟨ebm_avol_format#(m; ; avol0, err1)⟩ (avol = avol0 ∧ err = err1))))

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 14:
avols = ∅, n = m, v = default-volid ⊦ ⟪fail_or_success#(; ; err); if err = ESUCCESS then avols[v] := fill(mkabstractvolume(n), erased)⟫ ( (err = ESUCCESS → ⟨ebm_avol_format#(m; ; avol0, err1)⟩ (avol0 = abs(avols[default-volid]) ∧ ESUCCESS = err1)) ∧ (err ≠ ESUCCESS → (∀ avol. ⟨ebm_avol_format#(m; ; avol0, err1)⟩ (avol = avol0 ∧ err = err1))))

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ ¬ v ∈ ∅; (s)