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Proof step 20 from proof recovery (
previous step
)
err = err1, ebm-cons(avols0), ebm-cons(avols1), ebm-vol-inv(abs(avols1[default-volid])), default-volid ∈ avols1, avols1 ⊆ avols0, ⌊err1⌋ ⊦ ⟨avol := ?⟩ (avol0 = avol ∧ err1 = err)
Heuristic symbolic execution applied rule assign right
And closed the goal!
Rule argument
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