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Proof step 47 from proof recovery (previous step)

avol = abs(avols0[default-volid]), ebm-cons(avols0), ebm-cons(avols1), ebm-vol-inv(abs(avols1[default-volid])), default-volid ∈ avols0, default-volid ∈ avols1, avols1 ⊆ avols0 ⊦ (⌊ESUCCESS⌋ ∨ ESUCCESS = ESUCCESS) ∧ ⟨err := ESUCCESS; if err ≠ ESUCCESS then avol := ?⟩ (avol = abs(avols0[default-volid]) ∧ ESUCCESS = err)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 48:
avol = abs(avols0[default-volid]), ebm-cons(avols1), ebm-cons(avols0), ebm-vol-inv(abs(avols1[default-volid])), default-volid ∈ avols1, default-volid ∈ avols0, avols1 ⊆ avols0 ⊦ ⟨err := ESUCCESS; if err ≠ ESUCCESS then avol := ?⟩ (avol = abs(avols0[default-volid]) ∧ ESUCCESS = err)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ ⌊ESUCCESS⌋ ; (s)