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Proof step 99 from proof refine-read (previous step)

avols[default-volid][m2] = mapped(buf1, n1), m2 < # avols[default-volid], ebm-cons(avols), ebm-vol-inv(abs(avols[default-volid])), default-volid ∈ avols, n3 + n2 ≤ # buf2, m1 + n2 ≤ LEB_SIZE, ⌊err0⌋ ⊦ ∃ buf1. # buf1 = # buf2 ∧ range=(buf1, 0, buf2, 0, n3) ∧ range=(buf1, n3 + n2, buf2, n3 + n2, # buf2 - n3 + n2)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 100:
# buf2 = n0 + n3 + n2, avols[default-volid][m2] = mapped(buf1, n1), m2 < # avols[default-volid], ebm-cons(avols), ebm-vol-inv(abs(avols[default-volid])), default-volid ∈ avols, m1 + n2 ≤ LEB_SIZE, n3 + n2 ≤ # buf2, ⌊err0⌋ ⊦ ∃ buf1. # buf1 = # buf2 ∧ range=(buf1, 0, buf2, 0, n3) ∧ range=(buf1, n3 + n2, buf2, n3 + n2, n0)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# buf2, n3 + n2, n]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: # buf2, n3 + n2, n