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Proof step 5 from proof at-write-other (previous step)

# ax0 + 1 = # ndx, ∀ ndx, fs, adr. # ax0 = # ndx → fs[ax0, ndx][adr] = fs[adr] ∨ adr ∈ ax0 ⊦ fs[adr0 ' + ax0, ndx][adr] = fs[adr], adr = adr0, adr ∈ ax0

User applied rule constructor cut

And obtained the following new goals

Rule argument

var: ndx

Additional information

Used simplifier rules: node-list freely generated by [], +;;% ⊦ # [] = 0; (s)% ⊦ m + n = 0 ↔ m = 0 ∧ n = 0; (ws)% ⊦ # ax = 0 ↔ ax = []; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic