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Proof step 7 from proof at-write-other (previous step)

# ax0 = # ndx0, ∀ ndx, fs, adr. # ndx0 = # ndx → fs[ax0, ndx][adr] = fs[adr] ∨ adr ∈ ax0 ⊦ fs[adr0, nd][ax0, ndx0][adr] = fs[adr], adr = adr0, adr ∈ ax0

User applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: ndx0, fs[adr0, nd], adr abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ adr ≠ adr0 → fs[adr0, nd][adr] = fs[adr]; (s) Used terms: ndx0, fs[adr0, nd], adr