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Proof step 15 from proof del-del-again (previous step)

inodekey(m) ∈ ks ⊦ # ks = 0, key ∈ (ri ⊖ ks) ⊖ inodekey(m) ↔ key ∈ ri ⊖ ks, ks = ∅, (key ∈ (ri ⊖ ks) ⊖ inodekey(m) ↔ key ∈ ri ⊖ ks) ∧ (key ∈ (ri ⊖ ks) ⊖ inodekey(m) → ((ri ⊖ ks) ⊖ inodekey(m))[key] = (ri ⊖ ks)[key])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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