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Proof step 16 from proof del-put-again (
previous step
)
key ∈ ri[inodekey(m), adr], inodekey(m) ∈ ks, key ∈ ri ⊦ # ks = 0, ri[inodekey(m), adr][key] = ri[key], ks = ∅, key.data?, key ∈ ks
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 17
:
⊦ key ≠ key0 → ri[key0, adr][key] = ri[key]
Rule argument
spec: store, inst: node-index name: At-other seq: ⊦ key ≠ key0 → ri[key0, adr][key] = ri[key] subst: [key, adr, key0, ri] → [key, adr, inodekey(m), ri] flags: <all paths>
Additional information
Used terms: key, adr, inodekey(m), ri