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Proof step 1 from proof in-write (conclusion)

# ax = # ndx ⊦ adr ∈ fs[ax, ndx] ↔ adr ∈ fs ∨ adr ∈ ax

User applied rule structural induction

And obtained the following new goals

Proof step 2:
#(adr0 + ax0) = # ndx, ∀ ndx, adr, fs. # ax0 = # ndx → (adr ∈ fs[ax0, ndx] ↔ adr ∈ fs ∨ adr ∈ ax0) ⊦ adr ∈ fs[adr0 + ax0, ndx] ↔ adr ∈ fs ∨ adr ∈ adr0 + ax0

Rule argument

indvar: ax

Additional information

Used simplifier rules: write-base: ⊦ fs[[], []] = fs;%address-list freely generated by [], +;;% ⊦ # [] = 0; (s)% ⊦ # ndx = 0 ↔ ndx = []; (s)% ⊦ ¬ adr ∈ []; (s)