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Proof step 8 from proof index-update-in (previous step)

# kx0 = # ax0, key ∈ ri[key0, adr][kx0, ax0], ∀ ax, key, ri. # ax0 = # ax → (key ∈ ri[kx0, ax] ↔ key ∈ ri ∨ key ∈ kx0) ⊦ key ∈ ri[key0, adr][kx0, ax0] ↔ key ∈ ri ∨ key = key0 ∨ key ∈ kx0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
# kx0 = # ax0, key ∈ ri[key0, adr][kx0, ax0], ∀ ax, key, ri. # ax0 = # ax → (key ∈ ri[kx0, ax] ↔ key ∈ ri ∨ key ∈ kx0) ⊦ key = key0, key ∈ ri, key ∈ kx0

Proof step 8 from proof index-update-in (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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