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Proof step 7 from proof keys-firstn (previous step)

∀ fs, ax1. firstn(# ax, keys(fs, ax) + keys(fs, ax1)) = keys(fs, ax) ⊦ firstn(# ax, keys(fs, ax) + keys(fs, ax1)) = keys(fs, ax)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: fs, ax1

Additional information

Used terms: fs, ax1