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Proof step 8 from proof keys-in-elim-last-oc (previous step)

⊦ fs[adr0].key ∈ keys(fs, ax1), ∃ ax2, ax3, adr1. adr ' + ax + adr0 ' + ax1 = ax2 + adr1 ' + ax3 ∧ fs[adr1].key = fs[adr0].key ∧ ¬ fs[adr1].key ∈ keys(fs, ax3)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: adr ' + ax, ax1, adr0

Additional information

Used simplifier rules: a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[address-list-set] Used terms: adr ' + ax, ax1, adr0