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Proof step 11 from proof keys-in-elim (previous step)

adr0 ∈ ax0, fs[adr0].key ∈ keys(fs, ax0), ∀ key, fs. key ∈ keys(fs, ax0) ↔ (∃ adr. adr ∈ ax0 ∧ fs[adr].key = key) ⊦ fs[adr0].key = fs[adr].key, ∃ adr. adr ∈ ax0 ∧ fs[adr].key = fs[adr0].key

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: adr0

Additional information

Used terms: adr0