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Proof step 3 from proof new-append (previous step)

∀ ax1, fs. new(ax + ax1, fs) ↔ new(ax, fs) ∧ new(ax1, fs) ⊦ new((adr + ax) + ax1, fs) ↔ new(adr + ax, fs) ∧ new(ax1, fs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ ax1, fs. new(ax + ax1, fs) ↔ new(ax, fs) ∧ new(ax1, fs) ⊦ new(ax + ax1, fs) ↔ new(ax, fs) ∧ new(ax1, fs), adr ∈ fs

Rule argument

Additional information

Used simplifier rules: new-rec: ⊦ new(adr ' + log, fs) ↔ ¬ adr ∈ fs ∧ new(log, fs);%a: ⊦ (ax + ax0) + ax1 = ax + ax0 + ax1; from specification list[address-list-set]% ⊦ adr + ax = adr ' + ax; (s)