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Proof step 4 from proof new-ext (previous step)

∀ fs. (∀ adr. adr ∈ log0 → ¬ adr ∈ fs) → new(log0, fs), ∀ adr0. adr0 = adr ∨ adr0 ∈ log0 → ¬ adr0 ∈ fs ⊦ ¬ adr ∈ fs ∧ new(log0, fs)

User applied rule all left

And obtained the following new goals

Proof step 5:
(∀ adr. adr ∈ log0 → ¬ adr ∈ fs) → new(log0, fs), ∀ adr0. adr0 = adr ∨ adr0 ∈ log0 → ¬ adr0 ∈ fs ⊦ ¬ adr ∈ fs ∧ new(log0, fs)

Rule argument

pos: left 1 terms: fs abort: F discard: T computed: T

Additional information

Used terms: fs