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Proof step 1 from proof new-inode-exists (conclusion)

⊦ ∃ ino. ¬ inodekey(ino) ∈ ks

User applied rule cut formula

And obtained the following new goals

Proof step 2:
∃ ino. ∀ ino0. inodekey(ino0) ∈ ks → ino0 < ino ⊦ ∃ ino. ¬ inodekey(ino) ∈ ks
Proof step 6:
⊦ ∃ ino. ¬ inodekey(ino) ∈ ks, ∃ ino. ∀ ino0. inodekey(ino0) ∈ ks → ino0 < ino

Rule argument

fma: ∃ ino. ∀ ino0. inodekey(ino0) ∈ ks → ino0 < ino

Additional information

Used formulas: ∃ ino. ∀ ino0. inodekey(ino0) ∈ ks → ino0 < ino