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Proof step 3 from proof new-not-new (previous step)

new(ax, fs), adr ∈ ax, adr ∈ fs ⊦

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 4:
new(adr0 + ax0, fs), adr ∈ fs, adr ∈ adr0 + ax0, ∀ fs, adr. ¬(new(ax0, fs) ∧ adr ∈ ax0 ∧ adr ∈ fs) ⊦

Rule argument

term: ax

Additional information

Used simplifier rules: address-list freely generated by [], +;;% ⊦ ¬ adr ∈ []; (s)