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Proof step 6 from proof new-write (previous step)

new(ax0, fs), ∀ fs, adr, nd. new(ax0, fs) → (new(ax0, fs[adr, nd]) ↔ ¬ adr ∈ ax0) ⊦ adr0 ≠ adr ∧ new(ax0, fs[adr, nd]) ↔ adr ≠ adr0 ∧ ¬ adr ∈ ax0, adr0 = adr, adr0 ∈ fs

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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