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Proof step 3 from proof read-write-other-fs (previous step)

⊦ fs[adr, nd][ax] = fs[ax], adr ∈ ax

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 4:
∀ fs, adr, nd. fs[adr, nd][ax0] = fs[ax0] ∨ adr ∈ ax0 ⊦ fs[adr, nd][adr0 + ax0] = fs[adr0 + ax0], adr ∈ adr0 + ax0

Rule argument

term: ax

Additional information

Used simplifier rules: read-base: ⊦ fs[[]] = [];%address-list freely generated by [], +;;