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Proof step 6 from proof write-app (previous step)

# ax1 = # ndx1, # ax = # ndx, ∀ ax1, ndx1, ndx0, fs. # ax1 = # ndx1 ∧ # ndx = # ndx0 → fs[ax + ax1, ndx0 + ndx1] = fs[ax, ndx0][ax1, ndx1] ⊦ fs[adr, nd][ax + ax1, ndx + ndx1] = fs[adr, nd][ax, ndx][ax1, ndx1]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: ax1, ndx1, ndx, fs[adr, nd]

Additional information

Used terms: ax1, ndx1, ndx, fs[adr, nd]